Because protocols need to be changed, improved, and fixed from time to time, it is essential to have a protocol negotiation step at the start of every networked interaction, and protocol requirements at the start of every store and forward communication.

But we also want anyone, anywhere, to be able to introduce new protocols, without having to coordinate with everyone else, as attempts to coordinate the introduction of new protocols have ground to a halt, as more and more people are involved in coordination and making decisions. The IETF is paralyzed and moribund.

So we need a large enough address space that anyone can give his protocol an identifier without fear of stepping on someone else's identifier. But this involves inefficiently long protocol identifiers, which can become painful if we have lots of protocol negotiation, where one system asks another system what protocols it supports. We might have lots of protocols in lots of variants each with long names.

So our system forms a guess as to the likelihood of a protocol, and then sends or requests enough bits to reliably identify that protocol. But this means it must estimate probabilities from limited data. If one's data is limited, priors matter, and thus a Bayesian approach is required.

The Bayesian prior is the probability of a probability, or, if this recursion is philosophically troubling, the probability of a frequency. We have an urn containing a very large number of samples, from which we have taken no or few samples. What proportion of samples in the urn will be discovered to have property X?

Let our prior estimate of probability that the proportion of samples in
the urn that are X is ρ be Ρ_{prior}(ρ)

Then our prior estimate of the chance P_{X} that the first
sample will be X is

P_{X} = ∫ Ρ_{prior}(ρ) × dρ

Then if we take one sample out of the urn, and it is indeed X, then we
update our prior by:

P_{new}(ρ) = ρ × P_{prior}(ρ) / P_{X}

The Beta distribution is

P_{αβ} (ρ)= ρ^{(α-1)} × (1-ρ)^{(β-1)}
/ B(α,β)

B(α,β) is the normalization ∫ ρ^{(α-1)} × (1-ρ)^{(β-1)}
× dρ

B(α,β) = Γ(α) × Γ(β) / Γ(α + β)

Γ(α) = (α - 1)! for positive integer α

Γ(1) = 1

Γ(α+1) = α Γ(α) for all α

It is convenient to take our prior to be a Beta distribution, for if our prior the proportion of samples that are X is the Beta distribution α,β, and we take three samples, one of which is X, and two of which are not X, then our new distribution is the Beta distribution α+1,β+2 If our distribution is the Beta distribution α,β, then the probability
that the next sample will be X is

α/(α+β)

If α and β are large, then the Beta distribution approximates a delta function

If α and β equal 1, then the Beta distribution assumes all probabilities equally likely.

That, of course, is a pretty good prior, which leads us to the
conclusion that if we have seen `n`

samples that are green,
and `m`

samples that are not green, then the probability of
the next sample being green is `(n+1)/(n+m+2)`

If our prior for the question “what proportion of men are mortal?” was a beta distribution, we would not be convinced that all men are mortal until we had first checked all men – thus a beta distribution is not always a plausible prior.

The weight of evidence is the inverse of entropy of P(ρ) – the
integral ∫Ρ_{prior}(ρ) × ln[Ρ_{prior}(ρ)] × dρ
the lower the entropy, the more we know about the distribution P(ρ),
hence the principle of maximum entropy – that our distribution should
faithfully represent the weight of our evidence, no stronger and no
weaker.

The principle of maximum entropy leaves us with the question of what
counts as evidence. To apply, we need to take into account *all*
evidence, and everything in the universe has some relevance.

Thus to answer the question “what proportion of men are mortal” the principle of maximum entropy, naively applied, leads to the conclusion that we cannot be sure that all men are mortal until we have first checked all men. If, however, we include amongst our priors the fact that all men are kin, then that all men are X, or no men are X has to have a considerably higher prior weighting than the proposition that fifty percent of men are X.

The Beta distribution is mathematically convenient, but unrealistic. That the universe exists, and we can observe it, already gives us more information than the uniform distribution, thus the principle of maximum entropy is not easy to apply.

Further, in networks, we usually care about the current state of the network, which is apt to change, thus we frequently need to apply a decay factor, so that what was once known with extremly high probability, is now only known with reasonably high probability. There is always some unknown, but finite, substantial, and growing, probability of a large change in the state of the network, rendering past evidence irrelevant.

Thus any adequately flexible representation of the state of the network
has to be complex, a fairly large body of data, more akin to a spam filter
than a boolean.

Suppose our prior is that the probability of that the proportion of
samples in the urn that are X is ρ is [P_{11} (ρ) + δ(ρ) +
δ(1-ρ)] / 3

= [1^{} / B(1,1) + δ(ρ) + δ(1−ρ)] / 3

We are allowing for a substantial likelihood of all X, or all not X.

If we draw out m + n samples, and find that m of them are X, and n of
them are not X, then the δ terms drop out, and our prior is, as usual the
Beta distribution

P_{m+1,n+1}(ρ) = ρ^{(m)} × (1-ρ)^{(n)} /
B(m+1,n+1) if neither m nor n is zero.

But suppose we draw out n samples, and all of them are X, or none of them are X.

Without loss of generality, we may suppose all of them are X.

Then what is our prior after n samples, all of them X?

After one sample, n=1, our new estimate is

2/3 × [ρ / B(1,1) + δ(1−ρ)]

= 2/3 × [ρ × Γ(2) / (Γ(1) × Γ(1)) + δ(1−ρ)]

= 2/3 × [ρ × Γ(3) / (Γ(2) × Γ(1) × 2) + δ(1−ρ)]

= 1/3 × ρ × B(2,1) + 2/3 × δ(1−ρ)

And our estimate that the second sample will also be X is

8/9

After two samples, n=2, our new estimate is

1/4 × ρAnd our estimate that the third sample will also be X is^{2}× B(3,1) + 3/4 × δ(1−ρ)

15/16By induction, after n samples, all of them members of category X, our new estimate for the probability distribution is:

1/(n+2) × ρOur estimate that the run will continue one more time is^{n}× B(n+1,1) + (n+1)/(n+2) × δ(1−ρ)

1 − (n+2)^{-2}

= (n+3)×(n+1)×(n+2)^{-2}

Our estimate that the run will continue forever is:

(n+1)/(n+2)

Which corresponds to our intuition on the question "all men are mortal"